CUET Preparation Today
If $x^2 +y^2 +2y +4x + 5 = 0, \, then \, \frac{x+y}{x-y}$ = __________. |
-3 $\frac{1}{3}$ -1 3 |
-3 |
x2 + y2 + 2y + 4x + 5 = 0 =x2 + y2 + 2y + 4x + 4 + 1 = 0 =x2 + 4x + 4 + y2 + 2y + 1 = 0 =(x + 2)2 + (y + 1)2 = 0 x = -2 y = -1 $\frac{x+y}{x-y}$ = $\frac{-2 -1}{-2 +1}$ = 3 |
