If $x^2 +y^2 +2y +4x + 5 = 0, \, then \, \frac{x+y}{x-y}$ = __________.
Answer & explanation
Correct answer: option 1
x2 + y2 + 2y + 4x + 5 = 0
=x2 + y2 + 2y + 4x + 4 + 1 = 0
=x2 + 4x + 4 + y2 + 2y + 1 = 0
=(x + 2)2 + (y + 1)2 = 0
x = -2
y = -1
$\frac{x+y}{x-y}$ = $\frac{-2 -1}{-2 +1}$ = 3