Match List-I with List-II
Choose the correct answer from the options given below. |
(A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(IV), (B)-(II), (C)-(II), (D)-(III) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) |
(A)-(IV), (B)-(II), (C)-(II), (D)-(III) |
The correct answer is Option (2) → (A)-(IV), (B)-(II), (C)-(II), (D)-(III) **
Compute each value: (A) Unit digit of $2^{11}$ Cycle of 2: $2,4,8,6$ (length 4) $11 \bmod 4 = 3$ → 3rd term = 8 → (IV) (B) Unit digit of $11^{132}$ Unit digit of 11 is 1 → $1^{132}=1$ → (II) (C) Remainder of $71 \times 73 \times 75$ mod 23 $71 \equiv 2$, $73 \equiv 4$, $75 \equiv 6$ (mod 23) Product = $2 \cdot 4 \cdot 6 = 48$ $48 \bmod 23 = 2$ → (I) (D) Remainder of $7^{30}$ mod 5 $7 \equiv 2$ mod 5 → $2^{30}$ Cycle of 2 mod 5: $2,4,3,1$ (length 4) $30 \bmod 4 = 2$ → 2nd term = 4 → (III) |