A rectangular paper of width 8cm and length 22cm rolled along it width and a cylinder is formed.

On the above Intimation, Solve the question given below

The volume of cylinder is

$98πcm^3$

Here, in this case, some point is to be noted:

1. Length of the rectangle will becomes circumference of the base of the cylinder.

2. Breadth of the rectangle will becomes height of the cylinder.

3. Area of the rectangle will becomes curved surface area of the cylinder.

*************************************************

Now, According to question:

Width of rectangle = 8 cm = height of cylinder.

Length of rectangle = 22 cm. = circumference of base circle of cylinder.

⇒ 2πr = 22 cm.

⇒ 2×\(\frac{22}{7}\)r = 22 cm.

⇒ r = \(\frac{7}{2}\) cm.

⇒ area of the base = πr² = π × \(\frac{7^2}{2^2}\) = \(\frac{49}{4}\)π

⇒ Volume of cylinder = area of base × height = \(\frac{49}{4}\)π × 8 = 98π cm³