A can complete a work in $11\frac{1}{2}$ days. B is 25% more efficient than A and C is 50% less efficient than B. Working together A, B and C will complete the same work
Answer & explanation
Correct answer: option 2
A = \( { 11}_{ 2}^{ 1} \) days.
Given, A : B : C
4 : 5
. : 2 : 1
Efficiency 8 : 10 : 5
⇒ Total work = 8 x \( { 11}_{ 2}^{ 1} \) = 92 units. .(Efficiency ×Days=Total work)
⇒ Time taken by A + B + C to complete whole work = \(\frac{92}{8+10+5}\) = \(\frac{92}{23}\) = 4 days. ..(\(\frac{Work}{Efficiency}\) = Time)