In sodium nitroprusside the oxidation number, coordination number and effective atomic number of iron are respectively:

+2, 6, 36

The correct answer is option (4) +2, 6, 36.

The formula of Sodium nitroprussiade is \(Na_2[Fe(CN)_5NO].2H_2O\). In sodium nitroprusside, the oxidation state of Fe is +2. The coordination number of Fe is 6. The effective atomic number (EAN) of Fe is 36.

The oxidation state of Fe can be determined by considering the charges of the other atoms in the complex. The sodium ions have a charge of +1, the cyanide ions have a charge of -1, and the nitro group has a charge of -1. Therefore, the oxidation state of Fe must be +2 in order for the complex to be neutral.

The coordination number of Fe can be determined by counting the number of ligands that are bonded to Fe. In sodium nitroprusside, Fe is bonded to 5 cyanide ions and 1 \(NO\) ion. Therefore, the coordination number of Fe is 6.

The effective atomic number (EAN) of Fe can be determined by adding the number of electrons in the Fe atom to the number of electrons donated by the ligands. The number of electrons in the Fe atom is 26. The number of electrons donated by the cyanide ions is 5 x 2 = 10. The number of electrons donated by the NO ion is 2. Therefore, the EAN of Fe is 26 -2 + 10 + 2 = 36.

Therefore, the oxidation number, coordination number, and effective atomic number of iron in sodium nitroprusside are +2, 6, and 36, respectively.