If a copper wire carries a direct current, the magnetic field associated with the current would be: |
Only inside the wire Only outside the wire Both inside and outside of the wire No magnetic field would exists due to direct current |
Both inside and outside of the wire |
The correct answer is Option (3) → Both inside and outside of the wire $B_{inside}=\frac{μ_0Ir}{2πR^2},B_{outside}=\frac{μ_0I}{2πr}$ Therefore, a magnetic field exists both inside and outside of the wire. |