A compound is formed by 2 elements P and Q. Atoms of element Q (as anions) makes ccp and those of P (as cations) fill all tertrahedral voids and also occupy half of the octahedral voids. What is the correct formula of this compound? |
\(P_2Q_5\) \(P_5Q_2\) \(P_2Q_3\) \(P_3Q_2\) |
\(P_5Q_2\) |
The correct answer is option 2. \(P_5Q_2\). Let us break down the process of determining the formula of the compound where elements \( P \) and \( Q \) form a cubic close-packed (ccp) structure: Cubic Close-Packed (CCP) Structure: In a cubic close-packed lattice (also known as face-centered cubic or FCC), the atoms are packed in a repeating pattern with each atom surrounded by 12 others. Tetrahedral Voids: For every atom in a ccp lattice, there are 2 tetrahedral voids. Octahedral Voids: For every atom in a ccp lattice, there is 1 octahedral void. Counting Atoms and Voids: The unit cell of a ccp lattice effectively contains 4 atoms. In this structure: Tetrahedral voids: Each unit cell contains \( 2 \times 4 = 8 \) tetrahedral voids. Octahedral voids: Each unit cell contains 4 octahedral voids. Given Conditions Atoms of Q form ccp lattice: The atoms of Q are arranged in the ccp structure, meaning there are 4 Q atoms per unit cell Atoms of P fill all tetrahedral voids and half of the octahedral voids: All the tetrahedral voids are filled by P atoms. Half of the octahedral voids are also filled by P atoms Detailed Calculation In a ccp unit cell, there are: 8 tetrahedral voids 4 octahedral voids Tetrahedral Voids: All 8 tetrahedral voids are filled by P atoms. So, there are 8 P atoms filling tetrahedral voids. Octahedral Voids: Half of the 4 octahedral voids are filled by P atoms, which means 2 P atoms are filling octahedral voids. Total P atoms = 8 (from tetrahedral voids) + 2 (from octahedral voids) = 10 P atoms. Total Q atoms in the unit cell = 4 (as Q forms the ccp lattice) Total P atoms = 10 The empirical formula would be: \(\text{Empirical Formula} = P_{10}Q_{4}\) To simplify this formula, divide the subscripts by their greatest common divisor, which is 2: \(\frac{P_{10}Q_{4}}{2} = P_{5}Q_{2}\) Conclusion The formula of the compound, where the atoms of \( P \) and \( Q \) are arranged according to the given structure and conditions, simplifies to \( P_5Q_2 \). Thus, the correct formula for the compound is (2) \( P_5Q_2 \) |