A ,B and C can independently complete the same task in 4, 6 and 12 days, respectively. In how many days will they be able to complete the same task if they work together?

$2\frac{1}{2}$ $2\frac{1}{4}$ 3 2

2

A = 4 days, B = 6 days, C = 12 days, ⇒ Time required by A + B + C to complete the work = \(\frac{12}{3+2+1}\) = \(\frac{12}{6}\) = 2 days,    ..(\(\frac{Work}{Efficiency}\) = Time)