If $p+\frac{1}{p}= 112,$ find $(p - 112)^{15}+\frac{1}{p^{15}}$.
Answer & explanation
Correct answer: option 2
If $p+\frac{1}{p}= 112,$
find $(p - 112)^{15}+\frac{1}{p^{15}}$
If $p+\frac{1}{p}= 112,$
= p - 112 = -$\frac{1}{p}$
Put this value in required equation,
$(p - 112)^{15}+\frac{1}{p^{15}}$ = ( -$\frac{1}{p}$)15 + $\frac{1}{p^{15}}$ = 0