In how many years the compound interest on Rs. 10,000 at the rate of 10% will be Rs. 2,100?

2 Years

The correct answer is Option (2) → 2 Years

Compound interest formula:

$A = P \left(1 + \frac{R}{100}\right)^t$

Where:

• $P$ (Principal): Rs. 10,000
• $CI$ (Compound Interest): Rs. 2,100
• $A$ (Total Amount): $P + CI = 10,000 + 2,100 =$ Rs. 12,100
• $R$ (Rate): 10%

Substituting the values into the formula:

$12,100 = 10,000 \left(1 + \frac{10}{100}\right)^t$$

Divide both sides by 10,000:

$\frac{12,100}{10,000} = (1.1)^t$

$1.21 = (1.1)^t$

Since $(1.1)^2 = 1.21$, we can see that:

$t = 2$

Therefore, the correct choice is 2 Years.