CUET Preparation Today
| What is $\int \frac{x^4}{1+x^{10}}$ |
$\tan^{-1}x^3+C$ $1/5\sin^{-1}x^5+C$ $1/5\tan^{-1}x^5+C$ $\tan^5x+C$ |
| $1/5\tan^{-1}x^5+C$ |
| Put $x^5=t$. Then the integral becomes $\int \frac{1}{5(1+t^2)}dt=1/5tan^{-1}t+C=1/5tan^{-1}x^5+C$ |
