Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2 m on the surface of A. what is the height of jump by the same person on the planet B?

Options:

6 m

$\frac{2}{3}$ m

$\frac{2}{9}$ m

18 m

Correct Answer:

18 m

Explanation:

$g_{A}=9 g_{B}, \frac{g_{A}}{g_{B}}=9$

on planet A, In jumping the man goes up to height hA = 2m

∴ PE gained by him is mgA hA

Same amount of work is done by jumping on planet B

∴ P.E. gained by him on planet mgB hB 

equating, mgA hA = mgB hB

gA hA = gB hB

$h_{B}=\frac{g_{A}}{g_{B}} h_{A}$ = 9 × 2 = 18 m

$\left[∵ \frac{g_A}{g_B}=9\right]$