\(\int \sin^{3}x dx\) equals1\(-\frac{3}{4}\cos x+\frac{1}{12}\cos^{3}x+C\)2\(-\frac{3}{4}\cos x+\frac{1}{12}\cos 3x+C\)3\(-\frac{4}{3} \cos x+\frac{1}{12}\cos^{3}x+C\)4NoneAnswer & explanation+Correct answer: option 2\(\sin 3x=3\sin x-4\sin^{3}x\)
