The sum of the present ages of A and B is 48 years. B is 4 years older than C. The ratio of the present ages of A and C is 4 : 7. What was B’s age two years ago?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 30 years
The ratio gives A and C with one unknown; B follows from C, and the sum of A and B fixes the unknown.
Let A \(=4k\) and C \(=7k\); then B \(=7k+4\)
A \(+\) B \(=4k+7k+4=48\), so \(11k=44\) and \(k=4\)
B \(=7\times4+4=32\) years now
B two years ago \(=32-2=30\) years