Practicing Success
Practicing Success
CUET Preparation Today
A plane electromagnetic wave of frequency 40 MHz travels in free space in the X-direction. At some point and at some instant, the electric field $\vec{E}$ has its maximum value of 750 N/C in Y-direction. |
| The propagation constant of the wave will be: |
$8.38 m^{–1}$ $0.838 m^{–1}$ $4.19 m^{–1}$ $0.419 m^{–1}$ |
| $0.838 m^{–1}$ |
| $\text{Propogation constant is }K = \frac{2\pi}{\lambda} = \frac{2\times 3.14}{7.5} = 0.838m^{-1}$ |
