Match List I with List II:
|
List I (Nitrogen oxides) |
List II (Oxidation number of nitrogen) |
| A. \(NO\) | I. \(+4\) |
| B. \(N_2O_4\) | II. \(+2\) |
| C. \(N_2O_3\) | III. \(+5\) |
| D. \(N_2O_5\) | IV. \(+3\) |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A-II, B-I, C-IV, D-III
In an oxide the oxidation number of oxygen is −2, and the sum of the oxidation numbers in a neutral molecule is zero. For NxOy: x × (oxidation number of N) = 2y.
A. NO — N = +2 (1 × N = 2). This matches II. +2.
B. N2O4 — 2N = 8, so N = +4. This matches I. +4.
C. N2O3 — 2N = 6, so N = +3. This matches IV. +3.
D. N2O5 — 2N = 10, so N = +5. This matches III. +5.
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic is not there in the latest NCERT book (2026-27), and it is also out of the CUET 2026 syllabus.
NCERT (Pre-rationalised edition, 2022-23):
Oxides of Nitrogen – “… Formula and oxidation state of nitrogen: N2O, +1; NO, +2; N2O3, +3; NO2, +4; N2O4, +4; N2O5, +5.”