Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Phase difference between two waves having same frequency (v) and same amplitude (A) is $2π/3$. If these waves superimpose each other, then resultant amplitude will be

Options:

2A

0

A

A2

Correct Answer:

A

Explanation:

$A_R=\sqrt{A^2+A^2+2A×A\cos θ}$

$=\sqrt{A^2+A^2+2A^2\cos\frac{2π}{3}}$

$=\sqrt{A^2+A^2+2A^2(-\frac{1}{2})}$

$\sqrt{A^2+A^2-A^2}=\sqrt{A^2}=A$