Phase difference between two waves having same frequency (v) and same amplitude (A) is $2π/3$. If these waves superimpose each other, then resultant amplitude will be
Answer & explanation
Correct answer: option 3
$A_R=\sqrt{A^2+A^2+2A×A\cos θ}$
$=\sqrt{A^2+A^2+2A^2\cos\frac{2π}{3}}$
$=\sqrt{A^2+A^2+2A^2(-\frac{1}{2})}$
$\sqrt{A^2+A^2-A^2}=\sqrt{A^2}=A$