Three sets A, B, C are such that $A = B ∩C$ and $B=C∩A$, then

$A⊂B$ $A⊃B$ $A \equiv B$ $A⊂B'$

$A \equiv B$

The correct answer is Option (3) → $A=B$ We have, $A = B ∩C$ and $B=C∩A$ $\Rightarrow A=(C∩A)∩C$ $\Rightarrow  A \equiv B$