CUET Preparation Today
The force between the plates of a parallel plate capacitor of capacitance C, distance between plates d and potential difference V is |
$\frac{CV^2}{2d}$ $\frac{CV^2}{d}$ $\frac{C^2V^2}{4πε_0d}$ $\frac{1}{2}ε_0\frac{}{}$ |
$\frac{C^2V^2}{4πε_0d}$ |
The correct answer is Option (3) → $\frac{C^2V^2}{4πε_0d}$ |
