There are two concentric metal shells of radii r1 and r2 (>r1). If the outer shell has a charge q and the inner shell is grounded, the charge on the inner shell is |
zero −(r1/r2)q r1r2q ∞ |
−(r1/r2)q |
Let the charge on inner shell be Q. Since it is grounded, the potential of the shell must be zero due to both charge on inner shell and that on outer.
$ V = \frac{kQ}{r_1} + \frac{kq}{r_2} = 0$
$\Rightarrow Q = -q \frac{r_2}{r_1}$ |