A force F = 20 + 10 y acts on a particle in ydirection where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is
Answer & explanation
Correct answer: option 4
Work done : W = \(\int_{y_1}^{y_2}\)F.dy
W = \(\int_{0}^{1}d\)(20 + 10y) dy = 25 J