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A force F = 20 + 10 y acts on a particle in ydirection where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is |
20 J 30 J 5 J 25 J |
25 J |
Work done : W = \(\int_{y_1}^{y_2}\)F.dy W = \(\int_{0}^{1}d\)(20 + 10y) dy = 25 J |
