Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

What is the ratio of the mean proportional between 24 and 150 and the third proportional between 12 and $6\sqrt{5}$?

Options:

2 : 1

1 : 2

1 : 4

4 : 1

Correct Answer:

4 : 1

Explanation:

Mean Proportional = √24 x 150 = √3600 = 60.

The third proportional x 

12 : 6√5 :: 6√5 : x

⇒ 12x = 6√5 x 6√5

⇒ 12x = 180 

⇒ x = 15,

The required ratio = 60 : 15 = 4 : 1.