Δ ABC is a right-angle triangle at B and tan A = $\frac{3}{4}$, then sin A + sin B + sin C will be equal to:
Answer & explanation
Correct answer: option 2
A detailed explanation for this question is coming soon.
Δ ABC is a right-angle triangle at B and tan A = $\frac{3}{4}$, then sin A + sin B + sin C will be equal to:
Correct answer: option 2
A detailed explanation for this question is coming soon.