\([CoF_6]^{3-}\) using valance bond theory can be explained as

Outer orbital, paramagnetic

The correct answer is option 2. Outer orbital, paramagnetic.

The central \(Co\) atom is \(sp^3d^2\) hybridized. It forms octahedral complex with paramagnetic behavior due to presence of \(4\) unpaired electrons. It forms outer orbital or high spin or spin free complex as it utilizes outer \(4d\) orbitals in \(sp^3d^2\) hybridization.