Equation of the tangent at the point P (t), where t is any parameter, to the parabola y2 = 4ax is
Answer & explanation
Correct answer: option 1
Coordinates of the point P are (at2, 2at)
Differentiating $y^2=4 a x \Rightarrow 2 y \frac{d y}{d x}=4 a$
$\Rightarrow \frac{d y}{d x}=\left.\frac{2 a}{y} \Rightarrow \frac{d y}{d x}\right|_P=\frac{2 a}{2 a t}=\frac{1}{t}$
∴ equation of tangent is
$y-2 a t=\frac{1}{t}\left(x-a t^2\right) \Rightarrow x-y t+a t^2=0$