Practicing Success
Two rods A and B of different materials are welded together as shown in figure. Their thermal conductivities are K1 and K2. The thermal conductivity of the composite rod will be : |
2(\({K_1 + K_2}\)) \(\frac{K_1 + K_2}{2}\) \(3\frac{K_1 + K_2}{2}\) \(K_1 + K_2\) |
\(\frac{K_1 + K_2}{2}\) |
R = \(\frac{l}{KA}\) \(\frac{1}{R}\) = \(\frac{1}{R_1}\) + \(\frac{1}{R_2}\) \(\frac{1}{\frac{l}{K_{eff}A}}\) = \(\frac{1}{\frac{l}{K_1A/2}}\) + \(\frac{1}{\frac{l}{K_2A/2}}\) On solving , K = \(\frac{K_1 +K_2}{2}\) |