Practicing Success
If $x^2 + 4y^2 + 3z^2 + \frac{19}{4} = 2\sqrt{3}(x = y+z)$, then the value of ( x - 4y + 3z) is |
$\frac{\sqrt{3}}{3}$ $2\sqrt{3}$ $\sqrt{3}$ $\frac{\sqrt{3}}{2}$ |
$\sqrt{3}$ |
$x^2 + 4y^2 + 3z^2 + \frac{19}{4} = 2\sqrt{3}(x = y+z)$, then the value of ( x - 4y + 3z) = ? we can find the values of the variables by = Coefficient of variables on right sides divide by coefficient of same variable on left side along with the signs as given below = = x = \(\sqrt {3}\) = y = \(\frac{\sqrt {3}}{4}\) = z = \(\frac{1}{\sqrt {3}}\) So the value of ( x - 4y + 3z) = ( \(\sqrt {3}\) - 4(\(\frac{\sqrt {3}}{4}\)) + 3( \(\frac{1}{\sqrt {3}}\))) = $\sqrt{3}$ |