What is the shape of the complex [Ni(CO)4]?
Answer & explanation
Correct answer: option 3
In [Ni(CO)4]
x + 4(0) = 0
x = 0
28Ni: [Ar]4s23d8
As CO is a strong field ligand, it will pair up all the electrons in d-orbitals and also the electrons of 4s orbital in the same 3d orbital. Hence the hybridisation will be sp3.
