Practicing Success
Let $f(x)=\tan ^{-1}(g(x))$, where g(x) is monotonically increasing for $0<x<\frac{\pi}{2}$. Then, f(x), is |
increasing on $(0, \pi / 2)$ decreasing on $(0, \pi / 2)$ increasing on $(0, \pi / 4)$ and decreasing on $(\pi / 4, \pi / 2)$ none of these |
increasing on $(0, \pi / 2)$ |
We have, $f(x)=\tan ^{-1}(g(x)) \Rightarrow f'(x)=\frac{1}{1+\{g(x)\}^2} \times \frac{d}{d x}(g(x))$ For f(x) to be increasing, we must have f'(x) > 0 $\Rightarrow \frac{1}{1+\{g(x)\}^2} g'(x)>0$ $\Rightarrow g'(x)>0$ $\Rightarrow x \in(0, \pi / 2)$ [Given] |