Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Linear Programming

Question:

The solution of a LPP with basic feasible solutions (0, 0), (10, 0), (0, 20), (10, 15) and objective function Max $Z=2x+3y$ is:

Options:

$x = 0,y=20, Max\, Z=60$

$x = 10, y = 15, Max\, Z=65$

$x = 10, y = 20, Max\, Z=70$

$x = 15, y = 10, Max\, Z=60$

Correct Answer:

$x = 10, y = 15, Max\, Z=65$

Explanation:
corner point     objective function
(x, y) Z(x, y) = 2x + 3y
(0, 0) Z(0, 0) = 0 + 0 = 0
(10, 0) Z(10, 0) = 20 + 0 = 20
(0, 20) Z(0, 20) = 0 + 60 = 60
(10, 15) Z(10, 15) = 20 + 45 = 65 (Z-max)