The number of all possible matrices of order \(2 \times 3\) with each element 0, 1 or 2 is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 729
A matrix of order \(2 \times 3\) has
\(2 \times 3 = 6\) elements
Each element can be chosen in 3 ways (0, 1 or 2), independently of the others. So the number of matrices is
\(3^{6} = 729\)