A body of mass 100 kg falls from a height of 10 m. Its increase in kinetic energy is : 

980 J

Potential energy at the initial position = mgh = 10 x 9.8 x 10 = 980 J

Let the final velocity of the body just before it touches the ground be v.

\(v^2 = u^2 + 2gh\)

\(v^2 = 0+ 2*9.8*10 = 196 \text{ m}^2/s^2\)

∴ Kinetic energy of the body just before it touches ground = \(\frac{1}{2}mv^2\)

  = \(\frac{1}{2}*10*196 = 980 \text{ J}\)

Hence, kinetic energy gained =initial potential energy.