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The angle of depression from the top of a tower to a point on the ground is 60°. If the distance between the foot of tower and the point on ground is 45 feet. Find the height of tower? |
\(\frac{10}{\sqrt {3}}\) 10\(\sqrt {3}\) 15\(\sqrt {3}\) 45\(\sqrt {3}\) |
45\(\sqrt {3}\) |
Let height of tower AB = h cm Tan 60° = \(\frac{h}{45}\) h = 45\(\sqrt {3}\) |
