If $\frac{a}{b}+\frac{b}{a}=-1$ and a - b = 2, then the value of $a^3 - b^3$ is:

0 $\frac{1}{2}$ 1 -1

0

$\frac{a}{b}+\frac{b}{a}=-1$  \(\frac{a^2 + b^2}{ab}\) = -1 a2 + b2 = -ab a - b = 2 a3 - b3 = ( a - b ) ( a2 + b2 + ab ) a3 - b3 = ( 2 ) ( -ab + ab ) a3 - b3 = 0