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If a + b = 9, \(\frac{2}{3}\)ab = 12, then find the value of a2 + b2+ 4. |
66 49 24
59 |
49 |
a + b = 9 \(\frac{2}{3}\)ab = 12 ab = 18 Now, ⇒ (a+b)2 = (9)2 ⇒ a2 + b2 + 2ab = 81 ⇒ a2 + b2 = 81 - 2\(\times\) 18 = 45 ⇒ a2 + b2 + 4 = 45 + 4 = 49 |
