Practicing Success

Target Exam

CUET

Subject

Biology

Chapter

Molecular Basis of Inheritance

Question:

A students was repeating the experiments of Alfred Hershey and Martha Chase (1952). Results obtained by him are shown in the given figure. Select the biomolecule that was radio actively labelled by the students for his experiment.

Options:

DNA of bacteriophage with radio active Phosphorous

Plasmid DNA of E. coli with radio active Sulphur

Proteins of bacteriophage with radio active Sulphur

Chromosomal mol DNA of E. coli with radio active Sulphur

Correct Answer:

DNA of bacteriophage with radio active Phosphorous

Explanation:

The correct answer is Option (1) -DNA of bacteriophage with radio active Phosphorous

Alfred Hershey and Martha Chase conducted an experiment. In this Hershey and Chase experiment, they used the sulfur labeled proteins and phosphorous labeled DNA of the phage. These phages were then allowed to infect bacteria. It was observed that the DNA entered the bacterial cells and was therefore concluded to be the genetic material. The progeny of the phages that were labeled with radioactive phosphorus remained labeled whereas the progeny of the phages labeled with radioactive sulfur were unlabeled. This confirmed that DNA and not protein is the genetic material.