If $P(x) = (x^3 - 8) ( x +1) \, and \ Q(x) = (x^3 +1) (x-2),$ the LCM of P(x) and Q(x) is :
Answer & explanation
Correct answer: option 2
We know that,
(a - b)3 = a3 - b3 - 3ab(a-b)
(a + b)3 = a3 + b3 + 3ab(a+b)
Given,
P(x) = (x3 - 8)(x + 1)
= P(x) = (x - 2)(x2 + 2x + 4)(x + 1)
Q(x) = (x3 + 1)(x - 2)
= Q(x) = (x + 1)(x2 - x + 1(x - 2)
Now,
The LCM of P(x) and Q(x) is = (x + 1)(x - 2)(x2 + 2x + 4)(x2 - x + 1)