If 3 tan θ = 4, then what is the value of 7 sinθ - 2 cos θ ?

12/5 4 22/5 17/5

22/5

3 tan θ = 4 tan θ = \(\frac{4}{3}\) { we know, tan θ = \(\frac{P}{B}\) } By using pythagoras theorem, P² + B² = H² 4² + 3² = H² H = 5 Now, 7 sinθ - 2 cos θ = 7 × \(\frac{4}{5}\) - 2 × \(\frac{3}{5}\) = \(\frac{28}{5}\) -  \(\frac{6}{5}\) = \(\frac{22}{5}\)