The value of $\frac{\tan 30^{\circ}+\tan 60^{\circ}}{\cos 30^{\circ}}$ is:
Answer & explanation
Correct answer: option 3
\(\frac{tan30º + tan60º}{cosº}\)
= \(\frac{1/√3 + √3}{√3/2}\)
= \(\frac{8}{3}\
The value of $\frac{\tan 30^{\circ}+\tan 60^{\circ}}{\cos 30^{\circ}}$ is:
Correct answer: option 3
\(\frac{tan30º + tan60º}{cosº}\)
= \(\frac{1/√3 + √3}{√3/2}\)
= \(\frac{8}{3}\