The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area?
Answer & explanation
Correct answer: option 3
Let us assume the length to be 10 and breadth as 10. So, the area i.e. l x b = 100
After increase in length i.e. 16
Area = l x b
100 = 16 x b
b = 6.25
Difference = 3.75
Difference in percentage = \(\frac{3.75 }{10 }\) x 100 = 37.5%