A particular solution of $\log(dy/dx)=3x+4y,y(0)=0$ is:
Answer & explanation
Correct answer: option 4
$\frac{dy}{dx}=e^{3x+4y}⇒e^{-4y}dy=e^{3xdx}⇒\frac{e^{-4y}}{-4}=\frac{e^{3x}}{3}+x;y(0)=0⇒c=-7/12$
$⇒3e^{-4y}=-4e^{3x}+7$
A particular solution of $\log(dy/dx)=3x+4y,y(0)=0$ is:
Correct answer: option 4
$\frac{dy}{dx}=e^{3x+4y}⇒e^{-4y}dy=e^{3xdx}⇒\frac{e^{-4y}}{-4}=\frac{e^{3x}}{3}+x;y(0)=0⇒c=-7/12$
$⇒3e^{-4y}=-4e^{3x}+7$