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The non-negative remainder when $7^{36}$ is divided by 5 is: |
1 2 3 4 |
1 |
The correct answer is Option (1) → 1 $7 \equiv 2 \ (\text{mod } 5)$ $7^{36} \equiv 2^{36} \ (\text{mod } 5)$ $2^{4} = 16 \equiv 1 \ (\text{mod } 5)$ $2^{36} = (2^{4})^{9} \equiv 1^{9} \equiv 1 \ (\text{mod } 5)$ $\text{Non-negative remainder} = 1$ |
