What is the average of first six natural numbers, which are multiples of 3?
Answer & explanation
Correct answer: option 1
Sum of first 6 natural numbers multiple of 3 = 3 + 6 + 9 + 12 + 15 + 18
= 63
Average = \(\frac{63}{6}\)
= 10.5
What is the average of first six natural numbers, which are multiples of 3?
Correct answer: option 1
Sum of first 6 natural numbers multiple of 3 = 3 + 6 + 9 + 12 + 15 + 18
= 63
Average = \(\frac{63}{6}\)
= 10.5