If $x + \frac{1}{x}= 8, $ then find the value of $\frac{5x}{x^2+1-6x}$.

2.5

If $x + \frac{1}{x}= 8, $

then find the value of $\frac{5x}{x^2+1-6x}$

We can write $\frac{5x}{x^2+1-6x}$ as $\frac{5}{x+\frac{1}{x}-6}$

So, according to the question,

$\frac{5}{x+\frac{1}{x}-6}$ = $\frac{5}{8-6}$

$\frac{5}{x+\frac{1}{x}-6}$ = $\frac{5}{2}$ = 2.5