A long straight wire AB carries current 10 A. A proton (P) travels with a speed $2×10^6 m/s$, parallel to the wire, at a distance 2 m from it in a direction opposite to the current as shown in figure. The force experienced by the proton is: $(μ_0=4π×10^{-7}NA^{-2})$

$3.2×10^{-19}N$

The correct answer is Option (3) → $3.2×10^{-19}N$