$\underset{x→0^-}{\lim}\frac{e^{[\sin x]}}{[x+1]}$, (where [ ] denotes the greatest integer) is
Answer & explanation
Correct answer: option 3
Since the function is not defined as $x → 0^–$ because [x + 1] = 0, therefore limit does not exist.
$\underset{x→0^-}{\lim}\frac{e^{[\sin x]}}{[x+1]}$, (where [ ] denotes the greatest integer) is
Correct answer: option 3
Since the function is not defined as $x → 0^–$ because [x + 1] = 0, therefore limit does not exist.