Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

Match the ions given in List-I with number of unpaired electrons given in List-II

List-I Ion

List-II Number of unpaired electrons

(A) $V^{2+}$

(I) 1

(B) $Cr^{2+}$

(II) 4

(C) $Ti^{2+}$

(III) 3

(D) $Cu^{2+}$

(IV) 2

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Correct Answer:

(A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Explanation:

The correct answer is Option (4) → (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

List-I Ion

List-II Number of unpaired electrons

(A) $V^{2+}$

(III) 3

(B) $Cr^{2+}$

(II) 4

(C) $Ti^{2+}$

(IV) 2

(D) $Cu^{2+}$

(I) 1

(A) V²⁺: Atomic number of V is 23 → [Ar] 4s² 3d³.

V²⁺ loses 2 electrons → 3d³ (high-spin in typical cases).

3 unpaired electrons in d orbitals. → (III) 3

(B) Cr²⁺: Atomic number of Cr is 24 → [Ar] 4s¹ 3d⁵.

Cr²⁺ → 3d⁴.

4 unpaired electrons. → (II) 4

(C) Ti²⁺: Atomic number of Ti is 22 → [Ar] 4s² 3d².

Ti²⁺ → 3d².

2 unpaired electrons. → (IV) 2

(D) Cu²⁺: Atomic number of Cu is 29 → [Ar] 4s¹ 3d¹⁰.

Cu²⁺ → 3d⁹.

1 unpaired electron (due to one hole in d orbitals). → (I) 1