A and B start moving towards each other from places X and Y respectively at the same time on the same day. The speed of A is 25% more than that of B. After meeting on the way, A and B take Z hours and 6\(\frac{1}{4}\) hours, respectively to reach their destination. What is the value of Z?
Answer & explanation
Correct answer: option 2
A : B
Speed 5 : 4 [25% = \(\frac{1}{4}\)]
SA = 5, SB = 4
tA = Z, tB = \(\frac{25}{4}\)
Here the formula is :
\(\sqrt {\frac{t_A}{t_B}}\) = \(\frac{S_B}{S_A}\)
ATQ
⇒ \(\sqrt {\frac{Z}{\frac{25}{44}}}\) = \(\frac{4}{5}\)
⇒ \(\sqrt {\frac{4Z}{25}}\) = \(\frac{4}{5}\)
square both sides
\(\frac{4Z}{25}\) = \(\frac{16}{25}\)
⇒ Z = 4 hours