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If x% of y + y% of 30 = 61% of xy, then x = |
$\frac{1}{2}$ $\frac{1}{3}$ 2 3 |
$\frac{1}{2}$ |
The correct answer is Option (1) → $\frac{1}{2}$ $x\% \,of\, y + y\% \,of\, 30 = 61\% \,of\, xy$ $⇒\frac{x}{100}×y+\frac{y}{100}×30=\frac{61}{100}×xy$ $⇒\frac{3y}{10}=\frac{60xy}{100x}$ $⇒1=\frac{20x}{10}$ $⇒x=\frac{10}{20}=\frac{1}{2}$ |
