The base of a 12 m-high wooden solid cone has a circumference of 44 m. Find its volume. (Use $π = \frac{22}{7}$)

616 cm³

We know that,

Volume =  \(\frac{1}{3}\)πr²h

Circumference =  2πr

We have,

Height of wooden solid cone = 12cm 

Circumference = 44cm 

Circumference = 2πr = 44

=  2 × \(\frac{22}{7}\) × r = 44 

= r = 7 cm  

The volume of the cone = \(\frac{1}{3}\) × \(\frac{22}{7}\) × 7 × 7 × 12 = 616 cm³